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/*
* This file is part of the flashrom project.
*
* Copyright 2024 Google LLC
*
* This program is free software; you can redistribute it and/or modify
* it under the terms of the GNU General Public License as published by
* the Free Software Foundation; version 2 of the License.
*
* This program is distributed in the hope that it will be useful,
* but WITHOUT ANY WARRANTY; without even the implied warranty of
* MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
* GNU General Public License for more details.
*/
#include <include/test.h>
#include <stdint.h>
#include <sys/time.h>
#include <time.h>
#include "programmer.h"
#include "tests.h"
static uint64_t now_us(void) {
#if HAVE_CLOCK_GETTIME == 1
struct timespec ts;
clock_gettime(CLOCK_MONOTONIC, &ts);
return (ts.tv_nsec / 1000) + (ts.tv_sec * 1000000);
#else
struct timeval tv;
gettimeofday(&tv, NULL);
return tv.tv_usec + (tv.tv_sec * 1000000);
#endif
}
static const int64_t min_sleep = CONFIG_DELAY_MINIMUM_SLEEP_US;
/*
* A short delay should delay for at least as long as requested,
* and more than 10x as long would be worrisome.
*
* This test could fail spuriously on a heavily-loaded system, or if we need
* to use gettimeofday() and a time change (such as DST) occurs during the
* test.
*/
void udelay_test_short(void **state) {
/*
* Delay for 100 microseconds, or short enough that we won't sleep.
* It's not useful to test the sleep path because we assume the OS won't
* sleep for less time than we ask.
*/
int64_t delay_us = 100;
if (delay_us >= min_sleep)
delay_us = min_sleep - 1;
/* No point in running this test if delay always sleeps. */
if (delay_us <= 0)
skip();
uint64_t start = now_us();
default_delay(delay_us);
uint64_t elapsed = now_us() - start;
assert_in_range(elapsed, delay_us, 10 * delay_us);
}
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