From 7f1a7229718d788f26a711374da83adc2689837f Mon Sep 17 00:00:00 2001 From: David Vernet Date: Mon, 5 Feb 2024 22:39:20 -0600 Subject: sched/fair: Do strict inequality check for busiest misfit task group In update_sd_pick_busiest(), when comparing two sched groups that are both of type group_misfit_task, we currently consider the new group as busier than the current busiest group even if the new group has the same misfit task load as the current busiest group. We can avoid some unnecessary writes if we instead only consider the newest group to be the busiest if it has a higher load than the current busiest. This matches the behavior of other group types where we compare load, such as two groups that are both overloaded. Let's update the group_misfit_task type comparison to also only update the busiest group in the event of strict inequality. Signed-off-by: David Vernet Signed-off-by: Ingo Molnar Reviewed-by: Vincent Guittot Reviewed-by: Valentin Schneider Link: https://lore.kernel.org/r/20240206043921.850302-3-void@manifault.com --- kernel/sched/fair.c | 2 +- 1 file changed, 1 insertion(+), 1 deletion(-) (limited to 'kernel/sched') diff --git a/kernel/sched/fair.c b/kernel/sched/fair.c index 41dda5311770..448520f4fe83 100644 --- a/kernel/sched/fair.c +++ b/kernel/sched/fair.c @@ -10032,7 +10032,7 @@ static bool update_sd_pick_busiest(struct lb_env *env, * If we have more than one misfit sg go with the biggest * misfit. */ - if (sgs->group_misfit_task_load < busiest->group_misfit_task_load) + if (sgs->group_misfit_task_load <= busiest->group_misfit_task_load) return false; break; -- cgit v1.2.3