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author | Nicolas Pitre <nico@cam.org> | 2005-12-21 12:26:25 -0500 |
---|---|---|
committer | Linus Torvalds <torvalds@g5.osdl.org> | 2005-12-22 09:17:39 -0800 |
commit | d6f029130fb83b36fb709a187275b0494035d689 (patch) | |
tree | 27a5f8fb9fe1fc0df911231b5d9913b246427039 /include/linux/preempt.h | |
parent | d5ea4e26602fa7f5141872f2c17a862f1974a73f (diff) | |
download | linux-d6f029130fb83b36fb709a187275b0494035d689.tar.gz linux-d6f029130fb83b36fb709a187275b0494035d689.tar.bz2 linux-d6f029130fb83b36fb709a187275b0494035d689.zip |
[PATCH] fix race with preempt_enable()
Currently a simple
void foo(void) { preempt_enable(); }
produces the following code on ARM:
foo:
bic r3, sp, #8128
bic r3, r3, #63
ldr r2, [r3, #4]
ldr r1, [r3, #0]
sub r2, r2, #1
tst r1, #4
str r2, [r3, #4]
blne preempt_schedule
mov pc, lr
The problem is that the TIF_NEED_RESCHED flag is loaded _before_ the
preemption count is stored back, hence any interrupt coming within that
3 instruction window causing TIF_NEED_RESCHED to be set won't be
seen and scheduling won't happen as it should.
Nothing currently prevents gcc from performing that reordering. There
is already a barrier() before the decrement of the preemption count, but
another one is needed between this and the TIF_NEED_RESCHED flag test
for proper code ordering.
Signed-off-by: Nicolas Pitre <nico@cam.org>
Acked-by: Nick Piggin <nickpiggin@yahoo.com.au>
Signed-off-by: Linus Torvalds <torvalds@osdl.org>
Diffstat (limited to 'include/linux/preempt.h')
-rw-r--r-- | include/linux/preempt.h | 1 |
1 files changed, 1 insertions, 0 deletions
diff --git a/include/linux/preempt.h b/include/linux/preempt.h index d9a2f5254a51..5769d14d1e6a 100644 --- a/include/linux/preempt.h +++ b/include/linux/preempt.h @@ -48,6 +48,7 @@ do { \ #define preempt_enable() \ do { \ preempt_enable_no_resched(); \ + barrier(); \ preempt_check_resched(); \ } while (0) |