debugfs: remove return value of debugfs_create_regset32()

No one checks the return value of debugfs_create_regset32(), as it's not
needed, so make the return value void, so that no one tries to do so in
the future.

Link: https://lore.kernel.org/r/20191122104453.GA2017837@kroah.com
Signed-off-by: Greg Kroah-Hartman <gregkh@linuxfoundation.org>

1 files changed, 3 insertions, 3 deletions

diff --git a/Documentation/filesystems/debugfs.txt b/Documentation/filesystems/debugfs.txt
index dc497b96fa4f..55336a47a110 100644
--- a/Documentation/filesystems/debugfs.txt
+++ b/Documentation/filesystems/debugfs.txt
@@ -164,9 +164,9 @@ file.
 	void __iomem *base;
     };
 
-    struct dentry *debugfs_create_regset32(const char *name, umode_t mode,
-				     struct dentry *parent,
-				     struct debugfs_regset32 *regset);
+    debugfs_create_regset32(const char *name, umode_t mode,
+			    struct dentry *parent,
+			    struct debugfs_regset32 *regset);
 
     void debugfs_print_regs32(struct seq_file *s, struct debugfs_reg32 *regs,
 			 int nregs, void __iomem *base, char *prefix);